Web2.1. Clearly plot and label the constraints. Show your calculations for drawing constrain line. The solution without calculation will not be accepted. 2.2. Develop and shade the feasible region. Use graph paper. 2.3. Compute all the corner points or extreme points and their coordinates (i.e. the values of x and y). Web(Solved): 3. Solve the following initial value problem dt2d2x5dtdx+6x=(2t3)et with x(0)=1 and dtd ... 3. Solve the following initial value problem d t 2 d 2 x?? 5 d t d x? + 6 x = (2 t? 3) e t …
Solve x^2-5x-6=0 Microsoft Math Solver
Web2x2-5x-6=0 Two solutions were found : x =(5-√73)/4=-0.886 x =(5+√73)/4= 3.386 Step by step solution : Step 1 :Equation at the end of step 1 : (2x2 - 5x) - 6 = 0 Step 2 :Trying to factor ... Web2 days ago · Rhed°88. Nancy found that x=1 is one solution to the quadratic equation (x+2)2=a. The value of a is 9. Solution: (1+2)^2 = (3)^2 = 9. Log in for more information. Added 15 minutes 37 seconds ago 4/12/2024 5:42:33 PM. blackpink concert ticket price 2019
Solve x^2-6x+5=0 Microsoft Math Solver
WebJul 31, 2024 · $$ (x^2+6x+8)\ln (5) = \ln (1)$$ then I divide both sides by $\ln (5)$ to set the polynomial to zero because we know $\ln (1) = 0$ . I will be left with: $$x^2+6x+8 = 0$$ Factoring this will give: $$ (x+2) (x+4) = 0 \implies x = -2, -4 $$ Then I checked my $x$ values I got $1$. So my question is did I do it correctly? algebra-precalculus Web2 days ago · 3. Rhed°88. Nancy found that x=1 is one solution to the quadratic equation (x+2)2=a. The value of a is 9. Solution: (1+2)^2 = (3)^2 = 9. Log in for more information. … WebSolve using formula. x 2+6x+5=0. Medium Solution Verified by Toppr x 2+6x+5=0 Solution of ax 2+bx+c are x= 2a−b± b 2−4ac ⇒ Here, x= 2−6± 36−20= 2−6± 16= 2−6±4 ⇒x=−5 or x=−1 Solve any question of Quadratic Equations with:- Patterns of problems > Was this answer helpful? 0 0 Similar questions Solve using formula. 5m 2−4m−2=0 Medium View solution > blackpink concert ticket price malaysia 2023