WebRelative position of second stone w.r.t. first is given by x 2 (t) – x 1 (t) = 15t. Since there is a linear relationship between x 2 (t) – x 1 (t) and t, therefore the graph is a straight line. For maximum separation, t = 8 s So maximum separation is 120 m. After 8 second, only the second stone would be in motion. WebClass 11 Physics Notes are free and will always remain free. We will keep adding updated notes, past papers, guess papers and other materials with time. We will also introduce a …

NCERT Solutions for Class 11 Physics Chapter 6 - VEDANTU

Web= bc n ^ a →. ( b → × c →) = a. ( b c n ^) = abc cosθ n ^ = abc cos 0 0 = abc The volume of the parallelepiped. Q6. Find the components along the x, y, and z axes of the angular momentum l of a particle whose position vector is r with components x, y, and z and whose momentum is p with components px, py and pz. WebBalbharati 11th Physics (11th) Chapter 6: Mechanical Properties of Solids solutions Concepts covered in Mechanical Properties of Solids are Elastic Behavior of Solids, … shoe guy warringal

CBSE NCERT Solutions for CBSE class 11 Physics - Embibe

WebClass 11 Physics NCERT Solutions for Chapter 14 Oscillations. These NCERT Solutions provide you with the answers to the question from the textbook, important questions from previous year question papers and … WebAnswer: (a) When the pebble is moving upward, the acceleration g is acting downward, so the force is acting downward is equal to F = mg = 0.05 kg x 10 ms -2 = 0.5 N. (b) In this case also F = mg = 0.05 x 10 = 0.5 N. (downwards). (c) The pebble is not at rest at highest point but has horizontal component of velocity. WebAnswer: (a) True, magnitude of the velocity of a body moving in a straight line may be equal to the speed of the body. (b) False, each component of a vector is always a vector, not scalar. (c) False, total path length can … race track electric